Redox Reactions And Electrochemistry Question 204
Question: For the redox reaction $ Mn{{O}^{-}}_4 $ $ + $ $ C_2O_4^{2-} $ $ + $ $ {{H}^{+}} $ $ \to M{{N}^{2+}} $ $ +CO_2 $ $ +H_2O $ the correct coefficients of the reactants for the balanced reaction are
Options:
A)
| $ MnO_4^{-} $ | $ C_2O_4^{2-} $ | $ {{H}^{+}} $ |
|---|---|---|
| 2 | 5 | 16 |
B)
| $ MnO_4^{-} $ | $ C_2O_4^{2-} $ | $ {{H}^{+}} $ |
|---|---|---|
| 16 | 5 | 2 |
C)
| $ MnO_4^{-} $ | $ C_2O_4^{2-} $ | $ {{H}^{+}} $ |
|---|---|---|
| 5 | 16 | 2 |
D)
| $ MnO_4^{-} $ | $ C_2O_4^{2-} $ | $ {{H}^{+}} $ |
|---|---|---|
| 2 | 16 | 5 |
Show Answer
Answer:
Correct Answer: A
Solution:
The balanced equation is $ 2MnO_4^{-}+5C_2O_4^{2-}+16H^{+}\to 2Mn^{2+}+10CO_2+8H_2O $
BETA
