Redox Reactions And Electrochemistry Question 207
Question: 25 mL of 0.50 M $ H_2O_2 $ , solution is added to 50 mL of 0.20 M $ KMnO_4 $ in acid solution. Which of the following statements is true-
Options:
A) 0.010 mole of oxygen is liberated
B) 0.005 mole of $ KMnO_4 $ are left
C) 0.030 g atom of oxygen is evolved.
D) 0.0025 mole $ H_2O_2 $ does not react with $ KMnO_4 $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] M eq. of $ KMnO_4=.2\times 50\times 5=50 $ M eq. of $ H_2O_2=2\times 25\times .5=25 $ M eq. of $ KMnO_4 $ remaining = (50-25)=25 Mole of $ KMnO_4 $ $ =\frac{25}{5}\times {{10}^{-3}}=5\times {{10}^{-3}}=.005 $
BETA
