Redox Reactions And Electrochemistry Question 210
Question: In the following conversion of chromite into soluble chromium salt $ 4Fe(CrO_2) _2+8Na_2CO_3+7O_2\to 2Fe_2O_3+8NaCrO_4+8CO_2 $ There is
Options:
A) Oxidation of Fe and Cr both and reduction of $ O_2 $
B) oxidation of Fe and reduction of Cr
C) oxidation of Fe and Cr both reduction of barbon
D) No redox reaction
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Answer:
Correct Answer: A
Solution:
[a] $ \underset{\begin{smallmatrix} \uparrow \\ +2 \end{smallmatrix}}{\mathop{F{{e}^{2+}}}},+\underset{\begin{smallmatrix} \uparrow \\ +3 \end{smallmatrix}}{\mathop{2CrO_2^{-}}},+\underset{\begin{smallmatrix} \uparrow \\ 0 \end{smallmatrix}}{\mathop{O_2}},\to \underset{\begin{smallmatrix} \uparrow \\ +3 \end{smallmatrix}}{\mathop{Fe_2}},\underset{\begin{smallmatrix} \uparrow \\ -2 \end{smallmatrix}}{\mathop{O_3}},+\underset{\begin{smallmatrix} \uparrow \\ +6 \end{smallmatrix}}{\mathop{CrO_4^{2-}}}, $ $ F{{e}^{2+}} $ and $ C{{r}^{3+}} $ are oxidized (increase in oxidation number) $ O_2 $ is reduced,
BETA
