Redox Reactions And Electrochemistry Question 236
Question: Oxidation number of $ N $ in $ {{(NH_4)}_2}SO_4 $ is [CPMT 1996]
Options:
A) - 1 / 3
- 1
- 1
D) - 3
Show Answer
Answer:
Correct Answer: D
Solution:
$ {{(NH_4)}_2}SO_4 $ - $ 2NH_4^{+}+SO_4^{2-} $ $ \overset{*}{\mathop{NH_4^{+}}}, $ $ x+4=+1;x=1-4=-3 $ .
 BETA
  BETA 
             
             
           
           
           
          