Redox Reactions And Electrochemistry Question 238
Question: The molar conductances of $ NaCl,,HCl $ and $ CH_3COONa $ at infinite dilution are 126.45, 426.16 and $ 91,oh{m^{-1}},cm^{2},mo{l^{-1}} $ respectively. The molar conductance of $ CH_3COOH $ at infinite dilution is [CBSE PMT 1997]
Options:
A) $ 201.28,oh{m^{-1}},cm^{2},mo{l^{-1}} $
B) $ 390.71,oh{m^{-1}}cm^{2},mo{l^{-1}} $
C) $ 698.28,oh{m^{-1}},cm^{2},mo{l^{-1}} $
D) $ 540.48,oh{m^{-1}}cm^{2},mo{l^{-1}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \wedge _m^{o}(CH_3COOH)= $ $ {{\wedge }^{o}}(CH_3COONa) $ $ +{{\wedge }^{o}}(HCl)-{{\wedge }^{o}}(NaCl) $ $ =91+426.16-126.45=390.71oh{m^{-1}}cm^{2}mo{l^{-1}} $ .
BETA
