A) $ HCHO $
B) $ CHCl_3 $
C) $ CH_3OH $
D) $ C_{12}H_{22}O_{11} $
Correct Answer: B
Oxidation number of C in $ HCHO=0 $ $ CHCl_3=+2 $ $ CH_3OH=-2 $ $ C_{12}H_{22}O_{11}=0 $
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