Redox Reactions And Electrochemistry Question 31
Question: In a cell that utilises the reaction $ Z{n_{(s)}}+2{H^{+}}(aq)\to $ $ Z{n^{2+}}(aq)+{H_{ 2(g)}} $ addition of $ H_2SO_4 $ to cathode compartment, will [AIEEE 2004]
Options:
A) Increase the E and shift equilibrium to the right
B) Lower the E and shift equilibrium to the right
C) Lower the E and shift equilibrium to the left
D) Increase the E and shift equilibrium to the left
Show Answer
Answer:
Correct Answer: A
Solution:
$ Z{n_{(s)}}+2{H^{+}} _{(aq)} $ - $ Zn _{(aq)}^{2+}+{H _{2(g)}} $
$ E_{Cell}=E_{cell}^{0}-\frac{.059}{2}\log \frac{[Z{n^{2+}}]}{{{[{H^{+}}]}^{2}}} $
When $ H_2SO_4 $ is added then $ [{H^{+}}] $ will increase therefore $ E_{Cell} $ will also increases and equilibrium will shift towards right.
BETA
