Redox Reactions And Electrochemistry Question 322
Question: When $ KMnO_4 $ is reduced with oxalic acid in acidic solution, the oxidation number of $ Mn $ changes from [MNR 1987; MP PET 2000; CBSE PMT 2000; UPSEAT 2000, 02; BHU 2003; AMU 2002]
Options:
A) 7 to 4
B) 6 to 4
C) 7 to 2
D) 4 to 2
Show Answer
Answer:
Correct Answer: C
Solution:
$ 5\underset{COOH}{\overset{COOH}{\mathop{|}}},+\overset{+7}{\mathop{2KMnO_4}},+3H_2SO_4\to $ $ K_2SO_4+\overset{+2,}{\mathop{2MnSO_4}},+10CO_2+8H_2O $ In this reaction oxidation state of $ Mn $ change from + 7 to + 2.
BETA
