Redox Reactions And Electrochemistry Question 365
Question: $ H_2O_2 $ reduces $ K_4Fe{{(CN)}_6} $ [MP PMT 1985]
Options:
A) In neutral solution
B) In acidic solution
C) In non-polar solvent
D) In alkaline solution
Show Answer
Answer:
Correct Answer: B
Solution:
When $ H_2O_2 $ reduces with $ K_4[Fe{{(CN)}_6}] $ . It is present in acidic solution.
$ 2K_4[Fe{{(CN)}_6}+H_2SO_4+H_2O_2\to $ $ 2K_3[Fe{{(CN)}_6}]+K_2SO_4+2H_2O $
BETA
