Redox Reactions And Electrochemistry Question 38
Question: For the cell reaction, $ 2C{e^{4+}}+Co\to 2C{e^{3+}}+C{o^{2+}} $ $ E{{{}^\circ } _{cell}} $ is 1.89 V. If $ E{{{}^\circ } _{C{e^{4+}}/C{e^{3+}}}} $ [Pb.CET 2000]
Options:
A) - 1.64 V
B) + 1.64 V
C) - 2.08 V
D) + 2.17 V
Show Answer
Answer:
Correct Answer: B
Solution:
In this cell Co is oxidised and it acts as anode and Ce acts as cathode. $ E_{cell}^{0}=E_{Cathode}^{0}-E_{Anode}^{0} $ $ =1.89=E_{cell}^{0}-(-0.28) $ $ E_{cell}^{0}=1.89+0.28=2.17 $ Volts.
BETA
