Redox Reactions And Electrochemistry Question 448
Question: At 25°C specific conductivity of a normal solution of KCl is 0.002765 mho $m^{-1}$. The resistance of cell is 400 ohms. The cell constant is [Pb.PMT 2004]
Options:
A) 0.815
B) 1.016
C) 1.106
D) 2.016
Show Answer
Answer:
Correct Answer: C
Solution:
Cell constant $ =\frac{\text{Specific conductivity}}{\text{Observed conductance}} $ $ =\frac{0.002765}{1/R} $ =0 $ .002765\times 400=1.106 $ .
BETA
