Redox Reactions And Electrochemistry Question 481
Question: On passing current through two cells, connected in series containing solution of $ AgNO_3 $ and $ CuSO_4 $ , 0.18 g of Ag is deposited. The amount of the Cu deposited is:
Options:
A) 0.529 g
B) 10.623 g
C) 0.0529 g
D) 1.2708 g
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Using Faraday’s second law of electrolysis, $ \frac{Weight,of,Cu,deposoited}{Weight,of,Ag,deposited}=\frac{Equ.,wt.,of,Cu}{Equ.,wt.,of,Ag} $
$ \Rightarrow \frac{w_{Cu}}{0.18}=\frac{63.5}{2}\times \frac{1}{108} $
$ \Rightarrow w_{Cu}=\frac{63.5\times 18}{2\times 108\times 100}=0.0529g. $
BETA
