Redox Reactions And Electrochemistry Question 50
Question: Which of the following expression is correct [Orissa JEE 2005]
Options:
A) $ \Delta G^{o}=-nFE_{cell}^{o} $
B) $ \Delta G^{o}=+nFE_{cell}^{o} $
C) $ \Delta G^{o}=-2.303RT nFE_{cell}^{o} $
D) $ \Delta G^{o}=-nF \log K_{C} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \Delta G^{o}=-2.303RT \log K_{eq} $ or $ \Delta G^{o}=-nFE_{cell}^{o} $
BETA
