Redox Reactions And Electrochemistry Question 516
Question: For a cell reaction involving two electron change, the standard EMF of the cell is 0.295 V at $ 2{}^\circ C $ . The equilibrium constant of the reaction at $ 25{}^\circ C $ will be:
Options:
A) $ 29.5\times {10^{-2}} $
B) 10
C) $ 1\times 10^{10} $
D) $ 2.95\times {10^{-10}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Using the relation, $ E{{{}^\circ } _{cell}}=\frac{2.303RT}{nF}\log K _{eq}=\frac{0.0591}{n}\log K _{eq} $
$ \therefore 0.295V=\frac{0.0591}{2}\log K_{eq} $ Or $ \log K_{eq}=\frac{2\times 0.295}{0.0591}=10 $ Or $ K_{eq}=1\times 10^{10} $
BETA
