Redox Reactions And Electrochemistry Question 540
Question: Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is $ 100\Omega . $ . The conductivity of this solution is $ 1.29S{m^{-1}} $ . Resistance of the same cell when filled with 0.02 M of the same solution is $ 520\Omega $ . The molar conductivity of 0.02 M solution of electrolyte will be
Options:
A) $ 1.24\times {10^{-4}},Sm^{2}mo{l^{-1}} $
B) $ 12.4\times {10^{-4}},Sm^{2}mo{l^{-1}} $
C) $ 124\times {10^{-4}},Sm^{2}mo{l^{-1}} $
D) $ 1240\times {10^{-4}},Sm^{2}mo{l^{-1}} $
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Answer:
Correct Answer: A
Solution:
[a] Conductivity $ (\kappa)=\frac{\ell }{R.a} $ $ \kappa =\frac{l}{R.a}; $ cell constant. $ ( \frac{l}{a} )~=1.29\times 100=129 $ Again conductivity of 0.02M solution $ \kappa =\frac{1}{520}\times 129 $ $ {\Lambda_{m}}=\frac{\kappa \times 1000}{M}=\frac{129}{520}\times \frac{1000}{0.02} $ $ =1.24\times {10^{-4}}S,m^{2}mo{l^{-1}} $
BETA
