Redox Reactions And Electrochemistry Question 549
Question: Electrode potentials $ ( E{}^\circ ) $ are given below:
$ C{u^{+}}/Cu=+0.52V, $ $ F{e^{3+}}/F{e^{2+}}=+0.77V, $ $ \frac{1}{2}I_2(s)/{I^{-}}=+0.54V, $ $ A{g^{+}}/Ag=+0.88V $ . Based on the above potentials, strongest oxidizing agent will be:
Options:
A) $ C{u^{+}} $
B) $ F{e^{3+}} $
C) $ A{g^{+}} $
D) $ I_2 $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Higher the value of reduction potential stronger will be the oxidising hence based on the given values $ A{g^{+}} $ will be strongest oxidizing agent.
BETA
