A) $ Hg_2Cl_2 $
B) $ HgCl_2 $
C) $ FeCl_2 $
D) $ PbCl_2 $
Correct Answer: B
$ E_{Hg^{2+}|Hg}^{\circ }>E_{Hg^{2+}|Hg}^{\circ }>E_{Fe^{2+}|Fe}^{\circ }>E_{Pb^{2+}|Pb}^{\circ }$
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