Redox Reactions And Electrochemistry Question 594
Question: The oxidation number of phosphorus in $ Ba{{(H_2PO_2)}_2} $ is
Options:
A) +3
B) +2
C) +1
D) - 1
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ B{{a}^{2+}}(H_2PO_2)_2^{-1\times 2}:H_2PO_2^{-}:2+x-4=-1 $
$ \Rightarrow x=+1 $
$ \therefore $ Oxidation state of P = + 1
BETA
