Redox Reactions And Electrochemistry Question 655
Question: On electrolyzing the molten chloride of metal $ 725ml $ of $ Cl_2 $ liberated at $ 25{}^\circ C $ and 740 mm Hg pressure at anode for every one gm of metal deposite at cathode. The formula of metal chloride is (GAM of metal $ =52.01 $ )
Options:
A) $ MCI $
B) $ MCI_2 $
C) $ MCI_3 $
D) $ MCI_4 $
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Answer:
Correct Answer: C
Solution:
[c] equivalents of metal produced = equivalents of $ Cl_2 $ gas produced $ MCl_{x} $ $ x_{M}={x_{Cl_2}} $ $ x\times n_{M}=2\times {n_{Cl_2}} $ $ x\times \frac{1}{52.01}=2\times \frac{740}{760}\times \frac{725\times {10^{-3}}}{0.0821\times 298} $
$ \Rightarrow $ $ x=3 $ $ MCl_3 $
BETA
