SATHEE: Redox Reactions And Electrochemistry Question 667

Redox Reactions And Electrochemistry Question 667

Question: $ {{M}^{+3}} $ ion loses $ 3{{e}^{-}} $ . Its oxidation number will be [CPMT 2002]

Options:

Show Answer

Answer:

Correct Answer: C

Solution:

2 × No. of $ {{e}^{-}} $ losses = Oxidation no. $ 2\times 3{{e}^{-}}=+6 $ .

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Redox Reactions And Electrochemistry Question 667

Question: $ {{M}^{+3}} $ ion loses $ 3{{e}^{-}} $ . Its oxidation number will be [CPMT 2002]

Options:

Answer:

Solution:

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