Redox Reactions And Electrochemistry Question 669
Question: Match List I with List II and select the correct answer using the code given below the lists:
| List-I | List-II |
|---|---|
| $ ZnZ{n^{2+}}(0.01M), $ $ Z{n^{2+}}(0.1M)Zn $ | (p) primary cell |
| 1 Coulomb | (q) Secondary cell |
| Dry Cell | (r) $ 6.24\times 10^{18} $ electrons |
| Lead storage cell | (s) Concentration cell |
Options:
A) A-s, B-r, C-p, D-q
B) A-p, B-q, C-r, D-s
C) A-q, B-r, C-s, D-p
D) A-s, B-p, C-q, D-r
Show Answer
Answer:
Correct Answer: A
Solution:
[a] is concentration cell.
[b] $ 1{e^{-}}=1.6\times {10^{-19}} $ colulomb
1 coulomb $ =\frac{10^{19}}{1.6}=6.24\times 10^{18} $
[c] Dry cell is a primary cell.
[d] Lead storage cell is secondary cell.
BETA
