Redox Reactions And Electrochemistry Question 720
Question: What will be the value of x, y and z in the following equation $ H_2C_2O_4+xH_2O_2\xrightarrow[{}]{{}} $ $ yCO_2+zH_2O $
Options:
A) 2, 1, 2
B) 1, 2, 2
C) 2, 2, 1
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
[b] (i) The half reaction for oxidation is, $ H_2C_2O_4\xrightarrow[{}]{{}}CO_2 $
Balancing carbon atoms on both sides, $ H_2C_2O_4\xrightarrow[{}]{{}}2CO_2 $
Balancing hydrogen atoms on both sides, $ H_2C_2O_4\xrightarrow[{}]{{}}2CO_2+2{{H}^{+}} $
Balancing the charge on both sides, $ H_2C_2O_4\xrightarrow[{}]{{}}2CO_2+2{{H}^{+}}+2{{e}^{-}} $ (balanced)
(ii) The half reaction for reduction is- $ H_2O_2\xrightarrow[{}]{{}}H_2O $
Balancing oxygen atoms on both sides, $ H_2O_2\xrightarrow[{}]{{}}2H_2O $
Balancing hydrogen atoms, $ H_2O_2+2{{H}^{+}}\xrightarrow[{}]{{}}2H_2O $
Balancing the charge, $ H_2O_2+2{{H}^{+}}+2{{e}^{-}}\xrightarrow[{}]{{}}2H_2O $(balanced)
Now, adding both equation, $ H_2C_2O_4+H_2O_2\xrightarrow[{}]{{}}2CO_2+2H_2O $ This is balanced equation.
BETA
