Redox Reactions And Electrochemistry Question 736
Question: The number of electrons to balance the following equation $ NO_3^{-}+4{H^{+}}+{e^{-}},\to ,2H_2O+NO $ is [IIT Screening 1991]
Options:
5
4
3
2
Show Answer
Answer:
Correct Answer: C
Solution:
$ NO_3^{-}+4{H^{+}}+3{e^{-}}\to 2H_2O+NO $ In this equation all the atoms are balanced. For balancing added $ 3{e^{-}} $ to $ L.H.S. $ we have, $ NO_3^{-}+4{H^{+}}+3{e^{-}}\to 2H_2O+NO $ .
BETA
