Redox Reactions And Electrochemistry Question 759
The oxidation potentials of the following half-cell reactions are given $ Zn\to Zn^{2+}+2{e^{-}};E^{o}= -0.76V $ , $ Fe\to Fe^{2+}+2{e^{-}};E^{o}= -0.44V $ what will be the emf of cell, whose cell-reaction is $ Fe^{2+}(aq)+Zn\to Zn^{2+}(aq)+Fe $ [MP PMT 2003]
Options:
A) - 1.20 V
B) + 0.32 V
C) - 0.32 V
D) + 1.20 V
Show Answer
Answer:
Correct Answer: B
Solution:
$ Fe^{+2}+Zn\to Zn^{2+}+Fe $ $ EMF={E_{cathode}}-{E_{anode}} $ $ =0.44-(0.76)=+0.32,V $ .
BETA
