Redox Reactions And Electrochemistry Question 94

Question: When 9.65 coulombs of electricity is passed through a solution of silver nitrate (atomic weight of $ Ag=107.87 $ taking as 108) the amount of silver deposited is [EAMCET 1992; KCET 2000]

Options:

A) 10.8 mg

B) 5.4 mg

C) 16.2 mg

D) 21.2 mg

Show Answer

Answer:

Correct Answer: A

Solution:

$ W_{Ag}=\frac{E_{Ag}\times Q}{96500}=\frac{108\times 9.65}{96500} $ $ =1.08\times {10^{-2}}gm=10.8,mg $



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