Solid State Question 179
Question: An element occurring in the $ bcc $ structure has $ 12.08\times 10^{23} $ unit cells. The total number of atoms of the element in these cells will be
[MP PET 1994]
Options:
A) $ 24.16\times 10^{23} $
B) $ 36.18\times 10^{23} $
C) $ 6.04\times 10^{23} $
D) $ 12.08\times 10^{23} $
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Answer:
Correct Answer: A
Solution:
There are two atoms in a bcc unit cell. So, number of atoms in $ 12.08\times 10^{23} $ unit cells $ =2\times 12.08\times 10^{23} $
$ =24.16\times 10^{23}atom $ .
BETA
