Solid State Question 19

Question: Which of the following has maximum value of cation/ anion ratio-

Options:

A) $ KCl $

B) $ NaCl $

C) $ CaF_2 $

D) $ MgCl_2 $

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Answer:

Correct Answer: C

Solution:

[c] Among the three options $ KCl $ , $ NaCl $ and $ MgCl_2 $ , the size of anion is same. So larger the cation, larger will be the cation/anion ratio i.e., $ KCl $ will have larger cation/anion ratio among the three. So, we left with two options $ KCl $ and $ CaF_2 $ . Among these two $ CaF_2 $ will have maximum value of cation/ anion ratio because decrease in ionic radii of anion from $ C{{l}^{-}} $ to $ {{F}^{-}} $ does not overcome the effect of decrease in ionic radii of cation from $ {{K}^{+}} $ to $ C{{a}^{2+}} $ .