Solid State Question 203
Question: In $ {{A}^{+}}{{B}^{-}} $ ionic compound, radii of $ {{A}^{+}} $ and $ {{B}^{-}} $ ions are $ 180pm $ and $ 187pm $ respectively. The crystal structure of this compound will be
Options:
A) $ NaCl $ type
B) $ CsCl $ type
C) $ ZnS $ type
D) Similar to diamond
Show Answer
Answer:
Correct Answer: B
Solution:
$ {r _{+}}/{r _{-}}=\frac{180}{187}=0.962 $ which lies in the range of $ 0.732-1.000 $ , hence co-ordination number = 8 i.e. the structure is $ CsCl $ type.
BETA
