Solid State Question 224
Question: $ CsBr $ crystal has $ bcc $ structure. It has an edge length of $ 4.3{AA}. $ The shortest interionic distance between $ C{{s}^{+}} $ and $ B{{r}^{-}} $ ions is
[IIT 1995]
Options:
A) $ 1.86{AA} $
B) $ 3.72{AA} $
C) $ 4.3{AA} $
D) $ 7.44{AA} $
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Answer:
Correct Answer: B
Solution:
Closest approach in bcc lattice $ =\frac{1}{2} $ of body diagonal $ =\frac{1}{2}\times \sqrt{3}a $
$ =\frac{\sqrt{3}}{2}\times 4.3=3.72{AA} $ .
BETA
