Solid State Question 231
Question: The number of unit cells in $ 58.5g $ of $ NaCl $ is nearly
[MP PMT 2000, 01]
Options:
A) $ 6\times 10^{20} $
B) $ 3\times 10^{22} $
C) $ 1.5\times 10^{23} $
D) $ 0.5\times 10^{24} $
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Answer:
Correct Answer: C
Solution:
$ 58.5gNaCl=1mole $
$ =6.02\times 10^{23}N{{a}^{+}}C{{l}^{-}}units $ . One unit cell contains $ 4N{{a}^{+}}C{{l}^{-}} $ units. Hence number of unit cell present $ =\frac{6.02\times 10^{23}}{4} $
$ =1.5\times 10^{23} $ .
BETA
