Solid State Question 232
Question: How many unit cells are present in a cube-shaped ideal crystal of $ NaCl $ of mass $ 1.00g $
[Atomic masses: $ Na=23,Cl=35.5] $ [AIEEE 2003]
Options:
A) $ 2.57\times 10^{21} $ unit cells
B) $ 5.14\times 10^{21} $ unit cells
C) $ 1.28\times 10^{21} $ unit cells
D) $ 1.71\times 10^{21} $ unit cells
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{1}{58.5}\times 6.023\times 10^{23}=1.029\times 10^{22} $ A unit cell contains $ 4N{{a}^{+}} $ ion and $ 4C{{l}^{-}} $ ions \Unit cell $ =\frac{1.029\times 10^{22}}{4} $
$ =2.57\times 10^{21} $ unit cell.
BETA
