SATHEE: Solid State Question 244

Solid State Question 244

Question: The edge of unit cell of FCC $ Xe $ crystal is $ 620pm $ . The radius of $ Xe $ atom is

[MP PET 2004]

Options:

A) 219.25 Pm

B) 235.16 Pm

C) 189.37 Pm

D) 209.87 Pm

Show Answer

Answer:

Correct Answer: A

Solution:

$ r=\frac{a}{2\sqrt{2}} $ ; $ r=\frac{620}{2\sqrt{2}}=219.25Pm $

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Solid State Question 244

Question: The edge of unit cell of FCC $ Xe $ crystal is $ 620pm $ . The radius of $ Xe $ atom is

Options:

Answer:

Solution:

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