[DPMT 2005]
A) $ \frac{4}{\sqrt{3}}r $
B) $ \frac{4}{\sqrt{2}}r $
C) $ 2r $
D) $ \frac{\sqrt{3}}{2}r $
Correct Answer: B
In FCC $ 4r=\sqrt{2}a $
$ a=\frac{4r}{\sqrt{2}} $
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