Solid State Question 249
Question: If $ NaCl $ is doped with $ {{10}^{-3}}mol\ %SrCl_2, $ then the concentration of cation vacancies will be
Options:
A) $ 1\times {{10}^{-3}}mol% $
B) $ 2\times {{10}^{-3}}mol% $
C) $ 3\times {{10}^{-3}}mol% $
D) $ 4\times {{10}^{-3}}mol% $
Show Answer
Answer:
Correct Answer: A
Solution:
As each $ S{{r}^{2+}} $ ion introduces one cation vacancy, therefore concentration of cation vacancies = mol % of $ SrCl_2 $ added.
BETA
