Solid State Question 265
Question: The number of unit cells in 58.5 g of NaCl is nearly
Options:
A) $ 6\times 10^{20} $
B) $ 1.5\times 10^{23} $
C) $ 3\times 10^{22} $
D) $ 0.5\times 10^{24} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] 58.5 g $ NaCl=1mol=6.02\times 10^{23}N{{a}^{+}}C{{l}^{-}} $ units One unit cell contains $ 4N{{a}^{+}}C{{l}^{-}} $ units. Hence number of unit cell present $ =\frac{6.02\times 10^{23}}{4}=1.5\times 10^{23} $
BETA
