Solid State Question 291
Question: In a face centred cubic lattice, atoms of A form the corner points and atoms of B form the face centred points. If two atoms of A are missing from the corner points, the formula of the ionic compound is:
Options:
A) $ AB_3 $
B) $ AB_4 $
C) $ A_2B_5 $
D) $ AB_2 $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] A form corner points and two atoms of A are missing from corner
$ \therefore $ Atoms at corner $ ( A )=6\times \frac{1}{8}=\frac{3}{4} $ Atoms at face centre $ ( B )=6\times \frac{1}{2}=3 $
$ \therefore {A _{3/4}}B_3i.e.,AB_4 $
BETA
