Solid State Question 296
Question: In a face centered cubic lattice atoms A are at the comer points and atoms B at the face centered points. If atom B is missing from one of the face centered points, the formula of the ionic compound is:
Options:
A) $ AB_2 $
B) $ A_5B_2 $
C) $ A_2B_3 $
D) $ A_2B_5 $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Number of atoms $ A=\frac{1}{8}\times 8=1 $ Number of atoms $ B=\frac{1}{2}\times 5=\frac{5}{2} $ (Since atom B is missing from one of the face centered point)
$ \therefore $ Formula of ionic compound $ =A{B _{5/2}}=A_2B_5 $
BETA
