Solid State Question 67
Question: The composition of sample of wustite is $ F{e _{0.93}}{O _{1.00}} $ . What percentage of the iron is present in the form of Fe (III)-
Options:
A) 14%
B) 15.05%
C) 17%
D) 29%
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ F{e _{0.93}}{O _{1.00}} $ Oxidation number of $ F{e _{0.93}} $ = + 2 (0.93 mol possess net + 2 charge)
Suppose x mol + 2 charge.
then 0.93 - x posses + 3 charge
Hence, $ x\times 2+3(0.93-x)=+2 $
$ x=0.79F{{e}^{2+}};F{{e}^{3+}}=0.14 $ $ F{{e}^{3+}}$%=$\frac{0.14}{0.93}\times 100=15.05% $
BETA
