Solid State Question 76
Question: In normal spinel structures $ MgAl_2O_4, $ the percentage of tetrahedral void occupied is
Options:
A) 12.5%
B) 25%
C) 50%
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Oxygen forms fcc structure in which $ M{{g}^{2+}} $ occupies tetrahedral voids and $ A{{l}^{3+}} $ ions occupies octahedral void per unit cell. Total number of tetrahedral voids $ =2\times 4=8 $
$ \therefore $ % tetrahedral void occupied $ =\frac{1}{8}\times 100 $
$ =12.5% $
BETA
