Solutions Question 161
Question: At a particular temperature, the vapour pressures of two liquids A and B are respectively 120 and 180 mm of mercury If 2 moles of A and 3 moles of B are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm of mercury)
Options:
A) 156
B) 145
C) 150
D) 108
Show Answer
Answer:
Correct Answer: A
Solution:
Vapour pressure of solution $ =P_{A}+P_{B} $
$ =P_A^{{}^\circ }X_{A}+P_B^{{}^\circ }X_{B}=\frac{120\times 2}{5}+\frac{180\times 3}{5} $ =156 mmHg
BETA
