Solutions Question 18
Question: $ 6.02\times 10^{20} $ molecules of urea are present in 100 ml of its solution. The concentration of urea solution is [AIEEE 2004]
Options:
A) 0.02 M
B) 0.01 M
C) 0.001 M
D) 0.1 M (Avogadro constant, $ N_{A}=6.02\times 10^{23}mo{l^{-1}}) $
Show Answer
Answer:
Correct Answer: B
Solution:
Mole of urea $ =\frac{6.02\times 10^{20}}{6.02\times 10^{23}}={10^{-3}} $ moles Conc. of solution (in molarity)
BETA
