A) Urea
B) $ 0.1M $ glucose
C) $ 0.1 M MgSO_4 $
D) $ 0.1 M BaCl_2 $
Correct Answer: D
$ \frac{P^{0}-P_{s}}{P^{0}}=molality \times \text{(1-}\alpha +x\alpha +y\alpha ) $ the value of $ P^{0}-P_{s} $ is maximum for $ BaCl_2 $ .
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