Solutions Question 201
Question: An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is [KCET 2002]
Options:
A) 0.02
1
20
180
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{P^{0}-Ps}{P^{0}}=\frac{18\times 18}{180\times 90}=0.01 $ .
BETA
