Solutions Question 239
The vapour pressure of pure liquid solvent A is 1 atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm. What is the mole fraction of component B in the solution'
Options:
A) 0.75
B) 0.25
C) 0.40
D) 0.60
Show Answer
Answer:
Correct Answer: B
Solution:
$ p=X_{A}p^{o}\cdot X_{A}=\frac{p}{p^{o}}=\frac{0.60,atm}{0.80,atm}=0.75 $ $ X_{B}=1-0.75=0.25 $
BETA
