Solutions Question 268
Question: How many grams of $ CH_3OH $ should be added to water to prepare $ 150,ml $ solution of $ 2,M,CH_3OH $ [CBSE PMT 1994]
Options:
A) 9.6
B) 2.4
C) $ 9.6\times 10^{3} $
D) $ 2.4\times 10^{3} $
Show Answer
Answer:
Correct Answer: A
Solution:
1000 ml of $ CH_3OH $ requires methanol = 32 g. 150 ml of 2 M $ CH_3OH $ requires methanol $ =\frac{32}{1000}\times 150\times 2=9.6,g $ .
BETA
