Solutions Question 345
Question: When 10g of a non-volatile solute is dissolved in 100 g of benzene, it raises boiling point by $ 1^{o}C $ then molecular mass of the solute is $ (K_{b} $ for benzene =2.53k-m-1) [BHU 2002]
Options:
A) 223 g
B) 233 g
C) 243 g
D) 253 g
Show Answer
Answer:
Correct Answer: D
Solution:
$ \Delta T_{b}=\frac{K_{b}\times w\times 1000}{m\times W} $
$ m=\frac{K_{b}\times w\times 1000}{\Delta T_{b}\times W} $
$ =\frac{2.53\times 10\times 1000}{1\times 100}=253g $ .
BETA
