Applications Of Derivatives Question 10
Question: The function $ \frac{x-2}{x+1},(x\ne -1) $ is increasing on the interval
Options:
A) $ (-\infty ,,0] $
B) [0, $ \infty $ )
R
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Since $ f’(x)=\frac{3}{{{(x+1)}^{2}}} $ is greater than ‘0’ in interval $ (-\infty ,,-1) \cup (-1,,\infty ), $ therefore $ f(x)=\frac{x-2}{x+1} $ is increasing in interval $ (-\infty ,,-1) \cup (-1,,\infty ) $ or R.
BETA
