Applications Of Derivatives Question 124
Question: Let f(x) and g(x) be differentiable for $ 0\le x\le 1 $ such that f(0)=0, g(0)=0, f(1)=6. Let there exists a real number c in (0, 1) such that f-= 2g…………. then the value of g(1) must be
Options:
A) 1
B) 3
C) $ -,2 $
D) $ -,1 $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Applying Rolle-s theorem to $ F(x)=f(x)-2g(x), $ we get $ F(0)=0 $
$ F(1)=f(1)-2g(1) $ Or $ 0=6-2g(1) $ Or $ g(1)=3 $
BETA
