Applications Of Derivatives Question 149
Question: The tangent to the curve $ y=2x^{2}-x+1 $ at a point P is parallel to $ y=3x+4, $ the co-ordinates of P are
[RPET 2003]
Options:
A) (2, 1)
B) (1, 2)
C) (- 1, 2)
D) (2, - 1)
Show Answer
Answer:
Correct Answer: B
Solution:
$ y=2x^{2}-x+1 $ . Let the coordinates of P is (h, k), then $ {{( \frac{dy}{dx} )} _{(h,k)}}=4h-1 $
Clearly $ 4h-1=3 $
therefore $ h=1 $
therefore $ k=2 $ ; \ P is (1, 2).
BETA
