Applications Of Derivatives Question 175
Question: A particle moves in a straight line so that $ s=\sqrt{t} $ , then its acceleration is proportional to
[MP PET 2004]
Options:
A) Velocity
B) (Velocity)3/2
C) (Velocity) 3
D) (Velocity)2
Show Answer
Answer:
Correct Answer: A
Solution:
Given $ s=\sqrt{t} $ . Now $ v=\frac{ds}{dt}=\frac{1}{2\sqrt{t}} $ Also $ a=\frac{dv}{dt}=\frac{-1}{2\times 2{{(t)}^{3/2}}} $
therefore $ a\propto \frac{1}{t\sqrt{t}} $ or $ a\propto v^{3} $ .
BETA
